Chinese Card Identity Explorer

Venomous Brutalizer — 剧毒蛮袭兽

Explore Venomous Brutalizer in Chinese across 1 printings and 1 sets, with Traditional and Simplified Chinese versions, card text, artwork and release details.

1Total Chinese printings
0ZHTTraditional Chinese
1ZHSSimplified Chinese
1Sets
2023Chinese history

Phyrexia: All Will Be One · ONE

Card overview

Mana cost: {2}{G}{G}
Card type: Creature — Phyrexian Knight
Latest rarity: Uncommon

Oracle text

Toxic 3 (Players dealt combat damage by this creature also get three poison counters.)
When this creature enters, you may pay {1}{G}. If you do, proliferate. (Choose any number of permanents and/or players, then give each another counter of each kind already there.)

Chinese printing milestones

These milestones are calculated from the Chinese printings currently recorded in the CTG database.

First recorded Chinese printing Phyrexia: All Will Be One (ONE) February 10, 2023

First Traditional Chinese printing Not recorded

First Simplified Chinese printing Phyrexia: All Will Be One (ONE) February 10, 2023

Language coverage Simplified Chinese only 0 bilingual set(s)

ZHT —

ZHS 剧毒蛮袭兽

Chinese names and language variants

The same Magic card may have different printed names or wording between Traditional and Simplified Chinese editions. The versions below preserve the name and text printed on each physical card.

Traditional Chinese

No Traditional Chinese printed name recorded.

Simplified Chinese

剧毒蛮袭兽

Traditional Chinese name history

No printed-name history recorded for this script.

Simplified Chinese name history

剧毒蛮袭兽 Phyrexia: All Will Be One (ONE) 2023

1 distinct printed name(s) · 1 distinct printed-text version(s)

Traditional vs Simplified Chinese

Compare matching Chinese printings by set and collector number. Missing cells indicate that the corresponding printing is not currently recorded in the database.

Phyrexia: All Will Be One ONE · #193 2023

Not recorded

剧毒蛮袭兽

Printed text

下毒3（受此生物战斗伤害的牌手还会得到三个中毒指示物。）
当剧毒蛮袭兽进战场时，你可以支付{1}{G}。若你如此作，则增殖。（选择任意数量的永久物和／或牌手，然后为其已有之每种指示物各多放置一个同类的指示物。）

View printing